![]() You can't directly search for bytearrays in bytearrays with in, so convert them to a string containing fixed length hex representations as substrings, as shown. Print tries to print something human readable, which succeeds only for the first two chars. Which will give you: there's a number of separate issues at play here: Output as redirected from the console: can't search in aBytes directly with the in operator, since aBytes isn't a string but an array of bytes. hex representations of the integer values of the bytes by: aBytes = b'\x00\x47\x40\x00\x13\x00\x00\xb0' If you don't want that, convert your bytes to e.g. ![]() Print will try to convert bytes to something human readable. No need to convert it to a string by str. In Python 3 you'll get bytes from a binary read, rather than a string. Not for some strange python sees first two numbers as and not as '\x47\x40', though the rest of header it sees in HEX? Is there a way to fix it? 'Data' drawers allow an easy way to generate statistical data, linear regression, and gaussian elimination. ![]() It's ideal if you need to enter large expressions or have accurate precision. Question: What am I doing wrong? I want to look for r'\x47\x40\x00' and find it. Magic Number Machine is a free, full-featured, graphically laid out, high-precision, scientific calculator for OS X 10.6 or later. You see? Python sees it as instead of '\x47\x40'Īnd if i search for in header - everything is ok. The program does NOT find this pattern (r'\x47\x40\x00') in the file header. The file has it inside, as you can see from the picture below. Then I look for pattern in it: if y in header: I read first 24 bytes of a file: with open (from_folder+"/"+i, "rb") as myfile: I have a program in Python which analyses file headers and decides which file type it is.
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